6/2/2023 0 Comments Tuple index out of range![]() It also does not print out a third value. These are the last two values in our list. The code prints out the values Goldfinch as well as Chaffinch. So, here is the code for our for loop: 1 for i in range(3, 6): The range() statement creates a list of numbers between a particular range so that we can iterate over the items in our list whose index numbers are in that range. We will do this using a for loop as well as a range() statement. ![]() Next, we print out the last three values. So, let’s start by declaring a tuple: 1 cities = ("Edinburgh", "London", "Southend", "Bristol", "Cambridge") To clarify, the tuple contains a list of United Kingdom cities. Let’s write a program that prints out the last three values in a tuple. ![]() Each value has its own index number: Robin so, take a look at a tuple: 1 birds = ("Robin", "Collared Dove", "Great Tit", "Goldfinch", "Chaffinch") Every subsequent value in a tuple is assigned a number that is one greater than the last. To clarify, tuples are indexed starting from 0. Source: careerkarma Inde圎rror: Python tuple index out of range – Discussion of the problem We also walk through an example scenario with this problem present so that we can figure out how to solve it. So, in this guide, we explain what this common Python error means and why it is raised. When you try to access an item in a tuple that does not exist, Python returns an error that says “Python tuple index out of range”.
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